Square Root Equation Solver

Solve √(ax + b) = c with visible algebra and an original-equation check. The verification step catches impossible and extraneous results.

Written and checked by TheToolNet Editorial Team · Last reviewed: September 19, 2026

Solve √(ax + b) = c

How to solve square root equations

  1. Isolate the radical on one side.
  2. Square both sides once.
  3. Solve the resulting equation.
  4. Substitute each candidate into the original equation.

For √(2x + 1) = 5, squaring gives 2x + 1 = 25, so x = 12. The check √(2·12 + 1) = √25 = 5 confirms the solution.

Why extraneous solutions happen

Squaring loses sign information: 3² and (−3)² are both 9. As a result, an equation produced after squaring can accept a value the original equation rejects. Also, the principal square root is never negative; √(expression) = −2 has no real solution even though squaring both sides would produce a candidate.

Frequently asked questions

Does this solver handle multiple radicals?

No. It is deliberately focused on one square root containing a linear expression. Multiple radicals may require repeated isolation and squaring.

What if the coefficient a is negative?

It is supported. The final candidate still must make the radicand nonnegative and satisfy the original equation.

Can I solve roots without a calculator?

For numerical roots, see how to calculate square roots quickly.

Reference